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7w^2+39w=0
a = 7; b = 39; c = 0;
Δ = b2-4ac
Δ = 392-4·7·0
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-39}{2*7}=\frac{-78}{14} =-5+4/7 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+39}{2*7}=\frac{0}{14} =0 $
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